The sides of the base of the rectangular parallelepiped are 6 cm and 8 cm.
The sides of the base of the rectangular parallelepiped are 6 cm and 8 cm. The area of the diagonal section is 70 cm ^ 2. Find the complete surface of this parallelepiped.
Since the parallelepiped is rectangular, all of its faces are rectangles.
Let’s construct a diagonal AC at the base of the parallelepiped.
By the Pythagorean theorem in the right-angled triangle ABC, we determine the length of the hypotenuse AC.
AC ^ 2 = AB ^ 2 + BC ^ 2 = 36 + 64 = 100.
AC = 10 cm.
The diagonal section of a parallelepiped is a rectangle АА1С1С.
Then Ssech = АА1 * АС.
AA1 = Ssection / AC = 70/10 = 7 cm.
Determine the area of the base of the parallelepiped.
Sbn = AB * AD = 6 * 8 = 48 cm2.
Determine the area of the lateral surface of the parallelepiped.
Sside = Ravsd * AA1 = 28 * 7 = 196 cm2.
Then Sпов = 2 * Sсн + Sides = 2 * 48 + 196 = 292 cm2.
Answer: The surface area of the parallelepiped is 292 cm2.