The sides of the first rectangle are 4 cm and 6 cm, and the sides of the second are 8 cm and 15 cm.

| February 12, 2021 | education

The sides of the first rectangle are 4 cm and 6 cm, and the sides of the second are 8 cm and 15 cm. How many times the area of the second rectangle is greater than the area of the first rectangle.

The length of the first (a1) = 6 cm;
The width of the first (b1) = 4 cm;
The length of the second (a2) = 15 cm;
Width of the second (b2) = 8 cm;
Area of the second (S1)> area of the first (S2) -b? time.

The area of the rectangle is calculated by the formula: Sppr. = a * b.
Find the area of the first rectangle:
1) 6 * 4 = 24 (cm ^ 2);
Next, let’s calculate the area of the second rectangle:
2) 15 * 8 = 120 (cm ^ 2);
And finally, we can answer the question of the problem:
3) 120: 24 = 5 times.
Answer: the area of the second rectangle is 5 times the area of the first rectangle.



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