The sides of the parallelogram are 10 and 55. The height lowered to the smaller side is 33.

univerkov | May 8, 2021 | education

The sides of the parallelogram are 10 and 55. The height lowered to the smaller side is 33. Find the height lowered to the second side of the parallelogram.

1. Vertices of the parallelogram – A, B, C, D. CD = 10 units. AD = 55 units. The heights BK and BH are drawn to the sides CD and AD, respectively. BK = 33 units. S is the area of the parallelogram.

2. S = СD х BК = 10 х 33 = 330 units of measurement².

3. S = AB x BH = 330 units².

BH = 330: 55 = 6 units.

Answer: BH = 6 units of measurement.

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