The sides of the parallelogram are 22 and 44. The height lowered to the smaller side is 33.

The sides of the parallelogram are 22 and 44. The height lowered to the smaller side is 33. Find the height lowered to the second side of the parallelogram.

Let ABCD be a parallelogram, AD = BC = 44 conventional units – the large side, AB = CD = 22 conventional units – the smaller side, BK = 33 conventional units – the height lowered to the CD side.
The parallelogram area is equal to:
S = ah,
where a is the side of the parallelogram, h is the height drawn to the side a.
S = CD * BK;
S = AD * BH.
Then the equality is true:
CD * BK = AD * BH.
Substitute the known values and solve the equation with one unknown:
22 * 33 = 44 * BH;
44 * BH = 726;
BH = 726/44;
BH = 16.5 conventional units.
Answer: BH = 16.5 conventional units.