The sides of the quadrangle are ABCD, AB = 12cm, BC = 8cm, CD = 10cm and AD = 4cm. Angles A and C are straight.

The sides of the quadrangle are ABCD, AB = 12cm, BC = 8cm, CD = 10cm and AD = 4cm. Angles A and C are straight. Find the area of a quadrilateral.

Let us construct the diagonal ВD, which divides the quadrilateral AВСD into two right-angled triangles AВD and VСD.
Savd = AВ * AD / 2 = 12 * 4/2 = 24 cm2.
Svsd = ВС * СD / 2 = 8 * 10/2 = 40 cm2.
Then Savd = Savd + Svsd = 24 + 40 = 64 cm2.
Answer: 64 cm2.



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