The sides of the quadrilateral ABCD are: AB = 11, AC = 7, CD = 9, AD = 3, and the corners A

The sides of the quadrilateral ABCD are: AB = 11, AC = 7, CD = 9, AD = 3, and the corners A and C are right. What is the area of a quadrangle.

The area of a given quadrangle cannot be found using ordinary formulas, so we divide the figure into smaller figures and find their area.

Draw the height DH to the side AB that divides the quadrangle into rectangle AHDC and triangle BCH.

AH = 9, BH = 2 cm.

AHDC area = 9 * 7 = 63.

Area BHD = (2 * 7) / 2 = 7.

Area ABCD = 63 + 7 = 70 cm ^ 2.

Answer: 70 cm ^ 2.



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