The sides of the rectangle are 12.4 cm and 26 cm. Find the angle between the diagonals.

In rectangle ABCD, side AB = 12.4 cm, side BC = 26 cm.

Triangle ABC is rectangular.

tg <ACB = AB / BC = 12.4: 26 ≈ 0.48;

<ACB ≈ 26 °;

О is the intersection point of the diagonals of the rectangle.

The OBC triangle is isosceles, since the diagonals in the rectangle are equal at the point

the intersections are halved.

Means <OCB = <OBC = 26 °;

The angles of a triangle add up to 180 °;

<BOC = 180 ° – 2 * 26 ° ≈ 128 °;

The sum of adjacent angles is 180 °, which means:

<BOA ≈ 180 ° – 128 ° ≈ 52 °.