The sides of the rectangle are 9 cm and 5 cm. How much its area is less than the area

The sides of the rectangle are 9 cm and 5 cm. How much its area is less than the area of a square, whose perimeter is equal to the perimeter of this rectangle.

1) What is the perimeter of the rectangle?

P = 2 * (9 + 5) = 2 * 14 = 28 (see)

2) What is the side of the square?

28: 4 = 7 (cm).

3) What is the area of the square?

S = 7 * 7 = 49 (cm ^ 2).

4) What is the area of the rectangle?

S = 9 * 5 = 45 (cm ^ 2).

4) How much is the area of the rectangle less than the area of the square?

49 – 45 = 4 (cm ^ 2).

Answer. 4 cm ^ 2.