# The sides of the rectangle are equal to 14cm and 7 in. What is the area of a square whose

**The sides of the rectangle are equal to 14cm and 7 in. What is the area of a square whose perimeter is equal to the perimeter of this rectangle?**

First of all, we calculate the perimeter of a rectangle, the sides of which are 14 cm and 7 dm (70 cm). To do this, we find the doubled sum of the two sides of the rectangle:

P = 2 (14 + 70) = 2 * 84 = 168 (cm).

By the condition of the problem, the perimeter of the rectangle is equal to the perimeter of the square, respectively, the perimeter of the square is also 168 cm.

Find the side length of the square by dividing the known perimeter by the number of sides, that is, by 4:

168: 4 = 42 (cm).

Now let’s calculate the area of a square with a side of 42 cm, having raised the length of the side to the square:

S = 42² = 1764 (cm²).

Answer: the area of the square is 1764 cm².