The sides of the rectangular are 35 and 21, and its smaller base is 10 cm. Find the area of the trapezoid.
| September 28, 2021 | education
Let’s draw the height of the CH. Quadrangle ABCN is a rectangle, then CH = AB = 21 cm, AH = BC = 10 cm.
In a right-angled triangle СDН, according to the Pythagorean theorem, we determine the length of the leg СD.
DH ^ 2 = CD ^ 2 – CH ^ 2 = 35 ^ 2 – 21 ^ 2 = 1225 – 441 = 784.
DН = 28 cm.
The length of the larger base is: AD = AH + DH = 10 + 28 = 38 cm.
Determine the area of the trapezoid.
Savsd = (ВС + АD) * СН / 2 = (10 + 38) * 21/2 = 504 cm2.
Answer: The area of the trapezoid is 504 cm2.
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