The sides of the triangle abs are 12 15 18. find the sides of a triangle A1B1C1

The sides of the triangle abs are 12 15 18. find the sides of a triangle A1B1C1 similar to this one if the ratio of their perimeters is 3 (Pabc / Pa1b1c1 = 3)

Triangles are called similar, the corresponding sides of which are proportional:

AB / A1B1 = BC / B1C1 = AC / A1C1 = k.

Based on this, we can say that the perimeters of such triangles are also proportional:

PAVS / PA1B1C1 = k.

Thus, we see:

PAVS / PA1B1C1 = 3;

AB / A1B1 = BC / B1C1 = AC / A1C1 = 3;

A1B1 = AB / 3;

A1B1 = 12/3 = 4 cm;

B1C1 = BC / 3;

B1C1 = 15/3 = 5 cm;

A1C1 = AC / 3;

A1C1 = 8/3 = 6 cm.

Answer: the sides of a triangle similar to the ABC triangle are equal to A1B1 = 4 cm, B1C1 = 5 cm, A1C1 = 6 cm.