The sides of the triangle are 1; 1; √2. find its corners.
| August 30, 2021 | education
We apply the cosine theorem for a triangle and determine the value of the angle ABC.
AC ^ 2 = AB ^ 2 + BC ^ 2 – 2 * AB * BC * CosABS.
2 = 1 + 1 – 2 * 1 * 1 * Cos ABC.
2 * CosABC = 2 – 2 = 0.
CosABC = 0.
Angle ABC = 90.
Since, by condition, AB = BC = 1 cm, then the triangle ABC is isosceles, then the angle BAC = BCA = (180 – 90) / 2 = 45.
Answer: The angles of the triangle are 90, 45, 45.
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