The sides of the triangle are 10cm, 15cm, 20cm. Find the sides of a similar triangle whose perimeter is 90cm.
| November 29, 2020 | education
The perimeter of the first triangle is 10 + 15 + 20 = 45. The perimeter of the second is 90. I designate the sides of the second triangle as X, Y, Z. X / 10 = Y / 15 = Z / 20 = 90/45 => 1) X = 90 * 10/45 = 20 2) Y = 90 * 15/45 = 30 3) Z = 90 * 20/45 = 40
Answer: the sides of a triangle like it are equal to 20, 30 and 40.
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