The sides of the triangle are 14cm 16cm 18cm. Find the radius of the circumscribed circle.

Knowing the lengths of the sides of the triangle, by Heron’s theorem, we determine the area of the triangle ABC

The perimeter of the ABC triangle is: Rasv = 14 + 16 + 18 = 48 cm, then the half-perimeter p = 48/2 = 24 cm.

Savs = √p * (p – AB) * (p – BC) * (p – AC) = √24 * 8 * 10 * 6 = √11520 = 48 * √5 cm2.

Determine the radius of the circumscribed circle.

R = AB * BC * AC / 4 * S = 16 * 14 * 18/4 * 48 * √5 = 42 / √5 = 42 * √5 / 5 = 8.4 * √5 cm.

Answer: The radius of the circumscribed circle is 8.4 * √5 cm.



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