The sides of the triangle are 3 cm, 5 cm, and 7 cm. Find the corner of the triangle opposite to the side equal to 7 cm.

Cosine solution:
Cosine theorem: a2 = b2 + c2 – 2bccosα.
Instead of letters, we substitute numbers and it turns out:
7 ^ 2 = 3 ^ 2 + 8 ^ 2-2 * 3 * 8cosα.
49 = 9 + 64-48cosα
49 = 73-48cosα
49-73 = -48cosα
-48cosα = -24
cosα = 0.5
α = 60 °
Answer: the angle of the triangle of the opposite side is α = 60 °



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