The sides of the triangle are 7 cm and 4 cm, and the height drawn to the large side is 6 cm.

The sides of the triangle are 7 cm and 4 cm, and the height drawn to the large side is 6 cm. Find the height drawn to the other side.

First, find the area S of this triangle.

In the wording of the condition for this task, it is reported that the length of the height drawn to the larger of the two sides of the triangle is 6 cm.

Since the length of the larger side of this triangle is 7 cm, the area S of this triangle is:

S = 7 * 6/2 = 7 * 3 = 21 cm ^ 2.

Let us denote by h the length of the height drawn to the side with a length of 4 cm.

Then we can make the following equation:

4 * h / 2 = 21,

solving which, we get:

2 * h = 21;

h = 21/2 = 10.5 cm.

Answer: 10.5 cm.