The sides of the triangle are equal to 10cm and 17cm. Find the height of the triangle, lowered to the base, equal to 21cm.
In this problem, we have three sides of a triangle, which we denote as a = 10 cm, b = 17 cm,
c = 21 cm.In order to find the height h lowered to the base c = 21 cm, we use
formulas for the area of a triangle: Heron’s formula and the formula through the height and base.
According to Heron’s formula, we can calculate the area of a triangle, first finding p –
semi-perimeter p = (a + b + c): 2 = (10 + 17 + 21): 2 = 48: 2 = 24 (cm).
And by inserting all the data, we get according to Heron’s formula S = square root of the product
p * (p – a) * (p – b) * (p – c) or
S = square root of product 24 * (24 – 10) * (24 – 17) * (24 – 21)
Hence S = 84 square cm. Now we will use the second formula for the area of a triangle,
where S = (h * c) / 2 that is 84 = (h * 21) / 2 or 168 = h * 21, then we find
h = 8 cm.