The sides of the triangle formed by the middle lines of this triangle is 5 dm 7 dm 10 dm Find the sides of this triangle

A triangle is three points that do not lie on one straight line, connected by segments. In this case, the points are called the vertices of the triangle, and the segments are called its sides.

The segment connecting the midpoints of its two sides is called the midline of the triangle. The middle line of the triangle is parallel to the third side, and its length is half the length of this side:

A1B1 = AB / 2 = 5 dm;

В1С1 = ВС / 2 = 7 dm;

A1C1 = AC / 2 = 10 dm.

Thus, the length of the sides of this triangle ΔABS will be equal to:

AB = A1B1 2;

AB = 5 2 = 10 dm;

ВС = В1С1 2

BC = 7 2 = 14 dm;

AC = A1C1 · 2;

AC = 10 2 = 20 dm.

Answer: AB length is 10 dm, BC length is 14 dm, AC length is 20 dm.