The simplest formula of the compound in which the mass fraction of chromium is 68.42% and the mass fraction of oxygen is 31.58%.

Mass ratio of elements in an unknown compound:

w (Cr): w (O) = 68.42: 31.58

Considering the atomic masses of the elements, let’s move on to the quantitative ratio:

n (Cr): n (O) = w (Cr) / M (Cr): w (O) / M (O) = 68.42 / 52: 31.58 / 16 = 1.31: 1.97 = 1: 1.5 = 2: 3

This means that in the unknown compound there are 3 oxygen atoms for every 2 chromium atoms.

Hence the simplest formula of the compound: Cr2O3 (chromium (III) oxide).

Answer: Cr2O3.



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