The skier descended the mountain with an initial speed of 8m / s and an acceleration of 0.6m / s².

| April 30, 2021 | education

The skier descended the mountain with an initial speed of 8m / s and an acceleration of 0.6m / s². What is the final speed of the skier, the length of the mountain, if the descent took 10 seconds.

a = 0.6 m / s2.

V0 = 8 m / s.

t = 10 s.

V -?

S -?

With uniformly accelerated movement, the path S (the length of the mountain) traversed by the body is determined by the formula: S = V0 * t + a * t ^ 2/2, where V0 is the initial speed of movement, t is the time of movement, a is the acceleration during movement.

S = 8 m / s * 10 s + 0.6 m / s2 * (10 s) ^ 2/2 = 110 m.

We express the speed of the skier at the end of the mountain V from the definition for acceleration: a = (V – V0) / t.

V = V0 + a * t.

V = 8 m / s + 0.6 m / s2 * 10 s = 14 m / s.

Answer: the length of the mountain S = 110 m, the final speed of the skier V = 14 m / s.



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