The skier went down the hill in 5 seconds, moving with a constant acceleration of 0.5 m / s

The skier went down the hill in 5 seconds, moving with a constant acceleration of 0.5 m / s squared at the beginning of the descent, his speed was equal to 18 km / h, the length of the hill.

Initial data: t (time of the skier’s descent from the hill) = 5 s; a (constant acceleration of the skier) = 0.5 m / s2; V0 (speed of the skier at the beginning of the descent) = 18 km / h (5 m / s).

The length of the slide (the distance traveled by the skier) is determined by the formula: S = V0 * t + 0.5 * a * t ^ 2.

Let’s make the calculation: S = 5 * 5 + 0.5 * 0.5 * 5 ^ 2 = 31.25 m.

Answer: The length of the slide from which the skier left is 31.25 m.