The slaked lime was affected by 3.15 g of pure nitric acid, what mass of calcium nitrate will be obtained

| July 7, 2021 | education

The slaked lime was affected by 3.15 g of pure nitric acid, what mass of calcium nitrate will be obtained if the mass fraction of the output is 0.98.

Let’s find the amount of the substance HNO3 by the formula:

n = m: M.

M (HNO3) = 63 g / mol.

n = 3.15 g: 63 g / mol = 0.05 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Ca (OH) 2 + 2HNO3 = Ca (NO3) 2 + 2H2O.

For 2 mol of HNO3, there is 1 mol of Ca (NO3) 2. The substances are in quantitative ratios of 2: 1. The amount of Ca (NO3) 2 is 2 times less than the amount of HNO3.

n (Ca (NO3) 2) = ½ n (HNO3) = 0.05: 2 = 0.025 mol.

Let us find the mass of Ca (NO3) 2 by the formula:

m = n × M,

M (Ca (NO3) 2) = 164 g / mol.

m = 0.025 mol × 164 g / mol = 4.1 g.

4.1 – 100%,

X – 98%,

X = (4.1 × 98%): 100% = 4.018 g

Answer: 4.018 g.



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