The sled rolled down the side of a 48 meter long mountain in 16 seconds. What is the speed of the sled at the end

The sled rolled down the side of a 48 meter long mountain in 16 seconds. What is the speed of the sled at the end of the descent? The sled movement can be considered uniformly accelerated.

We use the kinematic equation:
x = x0 ± (V0 * t ± (a * t ^ 2) / 2)
In our case, it is written like this:
48 = (a * 16 ^ 2) / 2
We removed V0, since the initial speed is 0.
256a / 2 = 48
128a = 48
a = 48/128 = 0.375 m / s ^ 2
Vfinal = Vinitial + a * t
Vk = 0 + 0.375 * 16
Vк = 6 m / s