The slope, 100 m long, the skier covered in 20 s, moving with an acceleration of 0.2 m / s2.

| July 25, 2021 | education

The slope, 100 m long, the skier covered in 20 s, moving with an acceleration of 0.2 m / s2. What is the speed of the skier at the start and end of the slope?

To find the values of the skier’s speed at the beginning and at the end of the traversed slope, we will use the formulas: S = L = Vн * t + a * t ^ 2/2, whence Vн = (L – a * t ^ 2/2) / t and Vк = Vн + a * t.

Variables: L – slope length (L = 100 m); a – acceleration of the skier (a = 0.2 m / s2); t is the duration of the descent (t = 20 s).

Calculation: a) Initial speed: Vн = (L – a * t ^ 2/2) / t = (100 – 0.2 * 20 ^ 2/2) / 20 = 3 m / s;
b) Final speed: Vк = Vн + a * t = 3 + 0.2 * 20 = 7 m / s.

Answer: The skier started downhill at a speed of 3 m / s, and at the end of the slope he had a speed of 7 m / s.



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