The small piston of a hydraulic press under the action of a force of 150N lowered by 20 cm.

| September 9, 2021 | education

The small piston of a hydraulic press under the action of a force of 150N lowered by 20 cm. Weight of the load lifted by a large piston 600N Determine how many times the area of the larger piston is greater than the area of the small one? To what height was the load lifted?

The fluid pressure on the pistons is the same and the ratio is true:
F1 / S1 = F2 / S2; F1 is the pressure force on the larger piston (F1 = 600 N), S1 is the area of the larger piston, F2 is the pressure force on the smaller piston (F2 = 150 N), S2 is the area of the smaller piston.
F1 / F2 = S1 / S2 = 600/150 = 4 (the area of the larger piston is 4 times larger).
When lowering the smaller piston from S1 is 4 times less than the area of S2, the lifting height of the larger piston will be 4 r. less than the lowering height of the small piston (h1 = h2 / 4 = 20/4 = 5 cm) due to the volume of the displaced liquid.



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