The small piston of the hydraulic press, under the action of a force of 600N, lowered by 12 cm.

The small piston of the hydraulic press, under the action of a force of 600N, lowered by 12 cm. At the same time, the large piston rose by 3 cm. What force acts from the side of the liquid on the large hornet.

Fm = 600 N.

Lm = 12 cm = 0.12 m.

Lb = 3 cm = 0.03 m.

Fb -?

The hydraulic press provides a gain in strength, but not a gain in performance. The mechanical work of the small piston is equal to the work of the large piston: Am = Ab.

The work of the small piston Am is determined by the formula: Am = Fm * Lm, where Fm is the force of the small piston, Lm is the movement of the small piston.

The work of the large piston Ab is expressed by the formula: Ab = Fb * Lb, where Fb is the force of the large piston, Lb is the movement of the large piston.

Fm * Lm = Fb * Lb.

Fb = Fm * Lm / Lb.

Fb = 600 N * 0.12 m / 0.03 m = 2400 N.

Answer: the liquid acts on a large piston with a force of Fb = 2400 N.