The smaller angle of the isosceles trapezoid is 12 degrees. Find the sum of the two largest angles of this trapezoid.

Isosceles is a trapezoid in which the sides are equal, as well as the angles at the bases are equal:

AB = CD;

∠А = ∠D;

∠В = ∠С.

Since the sum of all the angles of the trapezoid is 360 °, and its smaller angles of the wound are 12 °, the sum of the large angles ∠В and ∠С will be equal to:

∠В + ∠С = 360 ° – ∠А – ∠D;

∠В + ∠С = 360 ° – 12 ° – 12 ° = 336 °.

∠В = ∠С = 336 ° / 2 = 168 °.

Answer: the sum of the great angles of an isosceles trapezoid is 336 °, and each of them is 168 °.