The solutions of 20 g sodium chloride and 20 g sodium sulfate were mixed. Calculate the mass of the sediment.

The reaction equation is as follows: NaCl2 + Na2SO4 -> Na2SO4 + 2NaCl We find the amount of substance in solutions: n (NaCl2) = m / M = 20/94 = 0.2 mol n (Na2SO4) = m / M = 20/142 = 0.14 mol Since the reaction is 1: 1, then the calculation is carried out using sodium chloride, because it is lacking n (NaSO4) = n (NaCl2) = 0.2 mol m (NASO4) = n * M = 0.2 mol * 236 g / mol = 47.2 g.
Answer: the mass of the precipitate is NaSO4 = 42.7 g.



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