# The specific heat of melting of ice is 334 kJ / kg. What power is needed for a heater to melt 6 kg

The specific heat of melting of ice is 334 kJ / kg. What power is needed for a heater to melt 6 kg of ice in 10 minutes at a temperature of 0 degrees Celsius.

Initial data: t (duration of ice melting) = 10 min (600 s); m (ice mass) = 6 kg; t0 (temperature at which ice was taken) = 0 ºС (melting point of ice).

Reference values: according to the condition λ (specific heat of melting of ice) = 334 kJ / kg (334 * 10 ^ 3 J / kg).

The required engine power is determined from the equality: λ * m = N * t, whence N = λ * m / t.

Calculation: N = 334 * 10 ^ 3 * 6/600 = 3340 W (3.34 kW).

Answer: We need a 3.34 kW heater.

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