The specific heat of vaporization of water is 2.3 KJ / kg. What does this number mean?

The specific heat of vaporization of water is 2.3 KJ / kg. What does this number mean? How much heat is required to convert 3 kg of water taken at the boiling point into steam?

The specific heat of vaporization of water λ = 2.3 kJ / kg is a physical constant that shows how much it is necessary to report 1 kg of water taken at a boiling point t = 100 ° C, thermal energy to transfer it from a liquid state of aggregation to a gaseous one.

λ = Q / m.

Q1 = λ * m1.

Q1 = 2.3 kJ / kg * 1 kg = 2.3 kJ.

Since for the conversion of m1 = 1 kg of water into steam, Q1 = 2.3 kJ of thermal energy is needed, then for the conversion of m = 3 kg, Q = 2.3 kJ / kg * 3 kg = 6.9 kJ.

Answer: to turn water into steam, it must be reported Q = 6.9 kJ of thermal energy.