The speed of a body falling to the ground at some point is 50 m / s. Where will this body be in 1s? Where was it 1s ago? Take the specified point as the origin of coordinates.
V = 50 m / s.
g = 10 m / s2.
t1 = 1 s.
t2 = -1 s.
x0 = 0.
The body falls to the ground only under the action of gravity with the acceleration of gravity g, therefore the dependence of the coordinates of the body x (t) changes according to the law: x (t) = x0 + g * t.
x1 (t1) = x0 + g * t1.
x1 (1 s) = 0 + 10 m / s2 * 1 s = 10 m.
x2 (t2) = x0 + g * t2.
x2 (-1 s) = 0 + 10 m / s2 * (-1 s) = -10 m.
Answer: for a time of 1 s before the moment of counting, the body had a coordinate x2 = – 10 m, after a time t1 = 1 s from the moment of counting, the body has a coordinate x1 = 10 m.
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