The speed of propagation of radio waves (the speed of light in a vacuum) is 3 * 10 ^ 8 m / s.

The speed of propagation of radio waves (the speed of light in a vacuum) is 3 * 10 ^ 8 m / s. Who will hear the voice of a soloist performing at a concert earlier: listeners sitting at a distance of 60 m from him, or radio listeners at a distance of 6,000 m? Take the speed of sound in air equal to 340 m / s.

s = 3 * 10 ^ 8 m / s.
S2 = 60 m.
S1 = 6000 m.
V2 = 340 m / s.
t1 -?
t2 -?
Earlier, the voice of the soloist will be heard by the one whose sound propagation time will be shorter.
The propagation time is determined by the formulas: t1 = S1 / s, t2 = S2 / V2.
t1 = 6000 m / 3 * 10 ^ 8 m / s = 2 * 10 ^ -5 m / s.
t2 = 60 m / 340 m / s = 0.176 s.
We see that t1 <t2, so radio listeners will be the first to hear the soloist’s voice.
Answer: radio listeners will be the first to hear the soloist’s voice.



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