The speed of the ball in the process of movement decreases from v1 = 20 m / s

The speed of the ball in the process of movement decreases from v1 = 20 m / s to v2 = 5 m / s. Ball mass m = 20g. What is the change in the momentum of the ball in this case?

To find out the change in the momentum of the specified ball, consider the formula: ΔPx = mw * (V2 – V1), where mw is the mass of the specified ball (mw = 20 g = 0.02 kg); V2 – decreased ball speed (V2 = 5 m / s); V1 – initial ball velocity (V1 = 20 m / s).

Let’s calculate: ΔРх = msh * (V2 – V1) = 0.02 * (5 – 20) = -0.3 kg * m / s.

Answer: The change (decrease) in the momentum of the indicated ball is 0.3 kg * m / s.