The speed of the body at the moment of impact on the Earth is 100 m / s.

The speed of the body at the moment of impact on the Earth is 100 m / s. Applying the law of conservation of energy, find the height from which the body began to fall.

To find the height from which the taken body began to fall, according to the condition, we use the law of conservation of energy: Еk0 + Еп0 = Еk1 + Еп1; 0 + m * g * h0 = m * V1 ^ 2/2 + 0, whence we express: h0 = V1 ^ 2 / 2g.

Variables and constants: V1 – velocity at the moment of impact (V1 = 100 m / s); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: h0 = V1 ^ 2 / 2g = 100 ^ 2 / (2 * 10) = 500 m.

Answer: The body taken should have started a free fall from a height of 500 m.