The speed of the current is 2.2 km / h. The boat’s own speed is 15.3 km / h.

The speed of the current is 2.2 km / h. The boat’s own speed is 15.3 km / h. What way did the boat go if it went downstream for 3 hours, and against 4.

Given:
v (current) = 2.2 km / h
v (boats) = 15.3 km / h
t (downstream) = 3 h
t (upstream) = 4 h

To find:
s (boats) -?

1) v (downstream) = v (current) + v (boats) = 2.2 + 15.3 = 17.5 (km / h);
2) s (downstream) = v (downstream) * t (downstream) = 17.5 * 3 = 52.5 (km);
3) v (upstream) = v (boats) – v (current) = 15.3 – 2.2 = 13.1 (km / h);
4) s (upstream) = v (upstream) * t (upstream) = 13.1 * 4 = 52.4 (km);
5) s (boats) = s (downstream) + s (upstream) = 52.5 + 52.4 = 104.9 km.

Answer: The boat passed 104.9 kilometers.



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