The speed of the helicopter is 5 times higher than the maximum speed of the polar owl, and 4 times lower than

The speed of the helicopter is 5 times higher than the maximum speed of the polar owl, and 4 times lower than the speed of the aircraft. How long does it take for an airplane to cover 4800 km? The maximum speed of a polar owl is 60 km / h.

To solve this problem, we first find the speed of the helicopter.

Since it is 5 times more than the speed of the polar owl, we get:

60 * 5 = 300 km / h.

We know that the speed of the helicopter is 4 times less than the speed of the airplane, so the speed of the airplane will be equal to:

300 * 4 = 1200 km / h.

We find time on the way.

To do this, we divide the indicated distance in the condition by the obtained airplane speed.

Will be:

4800/1200 = 4 hours.

Answer: It will take an airplane 4 hours to fly 4800 km.



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