The speed of the parachutist after opening the parachute decreased from 60 m / s to 5 m / s, in 1.1 s. find the acceleration

The speed of the parachutist after opening the parachute decreased from 60 m / s to 5 m / s, in 1.1 s. find the acceleration of the parachutist and the distance that he flew during this time.

Data: Vн (initial speed of the parachutist) = 60 m / s; Vk (final speed) = 5 m / s; t is the duration of the descent (t = 1.1 s).

1) Acceleration of the parachutist (we take into account the slow motion): a = (Vn – Vk) / t = (60 – 5) / 1.1 = 50 m / s2.

2) The distance that the parachutist managed to fly: S = (Vn + Vk) * t / 2 = (60 + 5) * 1.1 / 2 = 35.75 m.

Answer: The parachutist flew a distance of 35.75 m in 1.1 s with an acceleration of 50 m / s2.