The speed of the passenger elevator in the building is 3.5 m / s. How long does it take to reach this speed
| September 24, 2021 | education
The speed of the passenger elevator in the building is 3.5 m / s. How long does it take to reach this speed if the elevator moves with an acceleration of 3m / s²?
These tasks: V (speed of the passenger elevator at Moscow State University) = 3.5 m / s; a (the acceleration with which the lift starts to move) = 3 m / s2.
The duration of acceleration of a passenger elevator to a given speed is calculated by the formula: t = V / a.
Calculation: t = 3.5 / 3 = 1.17 s.
Answer: The passenger elevator accelerates to a speed of 3.5 m / s in 1.17 s.
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