The speed of two pedestrians is 5: 4. By what percentage is the speed of the first pedestrian faster than the second?
The speed of two pedestrians is 5: 4. By what percentage is the speed of the first pedestrian faster than the second? By what percentage is the speed of the second pedestrian less than the speed of the first?
Let us denote the speed of the second pedestrian through v.
According to the condition of the problem, the speeds of these two pedestrians are related as 5: 4, therefore, the speed of the first pedestrian is (5/4) v.
Let’s find by what percentage the speed of the first pedestrian is greater than the speed of the second:
100 * ((5/4) v – v) / v = 100 * ((5/4) v – (4/4) v) / v = 100 * (1/4) v / v = 100 * (1 / 4) = 100/4 = 25%.
Let’s find by what percentage the speed of the second pedestrian is less than the speed of the first:
100 * ((5/4) v – v) / ((5/4) v) = 100 * (1/4) v / ((5/4) v) = 100 * (1/4) * (4 / 5) = 100/5 = 20%.
Answer: the speed of the first pedestrian is 25% higher than the speed of the second, while the speed of the second pedestrian is 20% lower than the speed of the first.