The speed projections on the ОХ and ОУ axes change according to the equations Vx = 4-3t, Vy = 4t.

The speed projections on the ОХ and ОУ axes change according to the equations Vx = 4-3t, Vy = 4t. The acceleration with which the point is moving is equal?

Given: the equation for changing the projection of the speed of a given point on the OX axis: Vx = 4 – 3t; the equation for changing the projection of the speed of a given point on the axis ОY: Vy = 4t.

1) Projection of the set point acceleration onto the OX axis = Vx ‘= ax = (4 – 3t)’ = 0 – 3 * 1 = -3 m / s2.

2) The projection of the acceleration of the set point on the axis ОY = Vy ‘= ay = (4t)’ = 4 * 1 = 4 m / s2.

3) Acceleration with which a given point moves: a = √ (ax ^ 2 + ay ^ 2) = √ (3 ^ 2 + 4 ^ 2) = 5 m / s2.

Answer: The set point moves with an acceleration of 5 m / s2.