The spiral of an electric hotplate is made of nichrome wire 13.75 m long and a cross-sectional area of 0.1 mm2.
The spiral of an electric hotplate is made of nichrome wire 13.75 m long and a cross-sectional area of 0.1 mm2. The tile is designed for a voltage of 220V. Determine the current in the spiral of the tile.
l = 13.75 m.
S = 0.1 mm2.
U = 220 V.
ρ = 1 Ohm * mm2 / m.
I -?
According to Ohm’s law for a section of a circuit, the current I is directly proportional to the voltage at the ends of the conductor U and inversely proportional to its resistance R: I = U / R.
The resistance of a homogeneous cylindrical conductor R is found by the formula: R = ρ * l / S, where ρ is the resistivity of the material from which the conductor is made, l is the length of the conductor, S is the cross-sectional area.
The formula for determining the current strength will take the form: I = U * S / ρ * l.
I = 220 V * 0.1 mm2 / 1 Ohm * mm2 / m * 13.75 m = 1.6 A.
Answer: the current in the conductor is I = 1.6 A.