The spiral of an electric lamp runs 540 C of electricity for every 5 minutes. What is the current in the lamp?

We find the current strength in the conductor by the formula:
I = q / ∆t, where q is the charge that has passed through the cross-section of the spiral of the electric lamp (q = 540 C), ∆t is the charge passage time (∆t = 5 minutes = 5 * 60 s = 300 s).
Let’s calculate the current strength:
I = q / ∆t = 540/300 = 1.8 A.
Answer: The current in the lamp is 1.8 A.