The sportsman-driver submerged under water to a depth of 20 m. Determine the pressure acting on him

The sportsman-driver submerged under water to a depth of 20 m. Determine the pressure acting on him, if the atmospheric pressure is 10 kPa, the density of the water is 1000 kg / m3.

h = 20 m.

g = 10 N / kg.

Patm = 10 kPa = 10 * 10 ^ 3 Pa.

ρ = 1000 kg / m3.

P -?

The pressure P experienced by the athlete will be the sum of the atmospheric pressure Ratm and the hydrostatic pressure of the water Pg located above him: P = Ratm + Pg.

At a depth h, the value of the hydrostatic pressure Рг is determined by the formula: Рг = ρ * g * h, where ρ is the density of the liquid, in our case the density of the bottom, g is the acceleration of gravity.

Pg = 1000 kg / m3 * 10 N / kg * 20 m = 2 000 000 Pa = 2000 * 10 ^ 3 Pa = 2000 kPa.

P = 10 * 10 ^ 3 Pa + 2000 * 10 ^ 3 Pa = 2010 * 10 ^ 3 Pa = 2010 kPa.

Answer: a pressure of P = 2010 kPa acts on the athlete-driver.