The spring is lengthened by 4 cm under the action of the 2H force. What is its stiffness?
| January 9, 2021 | education
To determine the stiffness of the spring under consideration, we apply Hooke’s law: F = Fcont = k * Δx and k = F / Δx.
Variables: F – acting force (F = 2 N); Δx – elongation (deformation) of the considered spring (Δx = 4 cm; in SI Δx = 0.04 m).
Let’s make the calculation: k = F / Δx = 2 / 0.04 = 50 N / m.
Answer: The spring rate is 50 N / m.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
