The spring is stretched 4 cm. What is the potential energy of elastic deformation of the spring if the spring rate is 2000 N / m?
| March 3, 2021 | education
To calculate the potential energy of the taken spring after stretching, we apply the formula: A = k * Δx ^ 2/2.
Variables: k – spring rate (k = 2000 N / m); Δx is the tension of the spring (Δx = 4 cm = 0.04 m).
Let’s perform the calculation: A = k * Δx ^ 2/2 = 2000 * 0.042 / 2 = 1.6 N.
Answer: After stretching, the taken spring acquired a potential energy of elastic deformation of 1.6 J.
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