The spring is stretched to a length of 16 cm with a force of 16H, and then with a force of 8H

The spring is stretched to a length of 16 cm with a force of 16H, and then with a force of 8H to 10 cm. How long will the spring be if you stretch its force 6H

Data: l1 (length after stretching by force F1) = 0.16 m; F1 (first force) = 16 N; l2 (length after compression by force F2) = 0.1 m; F2 (compression force) = 8 N; F3 (considered tensile force) = 6 N.

1) Length without load: F1 / (l1 – l) = F2 / (l – l2).

16 / (0.16 – l) = 8 / (l – 0.1).

16l – 1.6 = 1.28 – 8l.

24l = 2.88 and l = 2.88 / 24 = 0.12 m.

2) Hardness: k = F1 / (l1 – l) = 16 / (0.16 – 0.12) = 400 N / m.

3) Length after stretching with a force of 6 N: l3 = l + Δl = l + F3 / k = 0.12 + 6/400 = 0.135 m.



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