The spring lengthened by 20 cm under the force of 20 N. What is its stiffness?
December 18, 2020 | education
| The spring lengthened by 20 cm under the force of 20 N. What is its stiffness?
By the formula k = F / elongation we find:
k = 20 N / 20 cm = 1 N / cm = 0.01 N / m
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