The spring-loaded pendulum oscillates at a frequency of 0.25 Hz. How many hesitations will he make in 10 seconds?
| August 3, 2021 | education
Data of the problem: ν (oscillation frequency of a given spring pendulum) = 0.25 Hz; t (duration of oscillation of the pendulum) = 10 s.
The number of oscillations of a given spring pendulum in 10 s is determined by the formula: n = t * ν.
Let’s calculate: n = 10 * 0.25 = 2.5 oscillations.
Answer: A given spring pendulum will make 2.5 oscillations in 10 seconds.
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