The spring pistol is loaded with a ball weighing 5 g. The spring with a stiffness of 100 N / m

The spring pistol is loaded with a ball weighing 5 g. The spring with a stiffness of 100 N / m is compressed by 10 cm.When fired vertically upwards, the ball rises to a height …

According to the law of conservation of energy:
Ep = Ep, Ep is the potential energy of the spring (Ep = (k * x ^ 2) / 2, k is the stiffness of the spring (k = 100 N / m), ∆l = the amount of deformation (∆l = 10 cm = 0.1 m)), Ep is the potential energy of the ball (Ep = m * g * h, m is the mass of the ball (m = 5 g = 5 * 10 ^ -3 kg), g is the acceleration of gravity (g = 10 m / s ^ 2 ), h – lifting height (m)).
(k * x ^ 2) / 2 = m * g * h.
Let’s express and calculate the height of the ball rise:
h = (k * x ^ 2) / (2 * g * h) = (100 * 0.1 ^ 2) / (2 * 10 * 5 * 10 ^ -3) = 10 m.
Answer: The ball will rise to a height of 10 m.