The spring rate is k = 500 N / m. The spring was stretched to 0.12m. Determine the potential elastic energy of the spring.
| December 16, 2020 | education
The potential energy is found by the formula
Ep = k * x ^ 2/2
Now, to find the potential energy, we just have to substitute the values
Ep = 500 * 0.12 ^ 2/2 = 3.6 (J)
Answer: Ep = 3.6 (J)
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